Math Rage Comics (part 4)























(Source)

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5 Comments.

  1. The ln(i^2) one is actually kind of interesting. How would you address it?

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  2. When a and b are real numbers, ln a^b = b ln a, but if not, you can’t garantee. e^ix = cos x + isen x, so e^ix = e^i(x+2pi). You can see that exponential is not one-to-one in the complex field, that’s why ln behaves so strangely.

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  3. e^ipi = -1
    ln -1 = i(pi + 2kpi), k integer
    If you let k = 1 and 3 at the same time
    2 = 6

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  4. Thanks, Miquei!

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