# Math game

Thanks to Secret Name for this submission!

Secret Name says:

I made this comic and wanted to share it with you. Tell me what you think about it in the comments!

### 11 thoughts on “Math game”

1. Wouldn’t saying Aleph-(null+one) solve the problem?

Similarly you could say Aleph-(n+1) for any Aleph-n, right?

1. Yes, you could. The trick is making quick questions so when you say X he quickly says X+1 and he doesn’t think about it.

2. Mark: That doesn’t work. What if I say Aleph(Aleph(null)). You say Aleph(Aleph(null)+1) and it’s the same number.

2. See, that is why the logician will say

2^x

where x is the absolute value of whatever you just said.

3. actually, you don’t need the absolute value part, just 2^(1000!), 2^(mole^mole), 2^(aleph_null) will be enough

it follows from Cantor-Bernstein, yes?

4. Well, as every cardinal number is also an ordinal number, and as I can use ordinal arithmetic with ordinal numbers, the “trick” of the comic falls apart: “Aleph_0 + 1” is by definition the least ordinal number that is greater than Aleph_0.

Aleph_0 + 1 is not a cardinality, but only a greater NUMBER was required.

Your trick would work if I said “1 + Aleph_0”, as that IS the same ordinal number as Aleph_0. But who would say that…?!

But Yung Hei is absolutely right, too, as his answer ALWAYS produces even a greater CARDINAL number. But for producing greater ORDINAL numbers, the procedure of the comic is completely satisfying.

So I guess, the moral of it all is this:

Don’t try to fuck with logicians… ðŸ˜‰

5. Nice math-fail by myself there – maybe I should read a little more carefully ðŸ˜³